Test:351 QNo:51

solve the differential equation (2y³+x)dy=ydx ,the curve passes through (0,1)

3 Answers

(2y³+x)dy=ydx
2y³ dy = ydx - xdy

2y dy = (ydx - xdy )/y²

2y dy = d(x/y)

âˆ«2y dy = âˆ«d(x/y)

y² = x/y + c

c = 1

y² = x/y + 1

y³ = x + y

so correct answer is B not A

1357

Manish Shankar ·2009-04-21 02:07:33

yes the answer is B

still showing -1 :o

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