Test:44 QNo:2

find dy/dx, y=log(tanlogx)

4 Answers

I'M GETTING sec²( log x )x. tan( log x ) and given is 2x*sin logx²

I'M ALSO GETTING sec²(log x)/x.tan(log x)

1357

Manish Shankar ·2010-06-30 07:16:08

sec²(logx)/xtan(logx)=1/x.sin(logx)cos(logx)=2/x.(2sinlogx.coslogx)=2/x.sin(2logx)=2/x.sinlogx²

it was easy :)

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