66
Sourup Nag
·2013-06-10 09:46:43
305 μC on the capacitor in the left, 190 μC on the capacitor in the middle and 115 μC on the capacitor in the right???
229
Dwijaraj Paul Chowdhury
·2013-06-10 18:48:35
Qleft= -325μC
Qmiddle= -230μC
Qright= 95μC
31
Rudra Sen
·2013-06-10 20:21:34
115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
31
Rudra Sen
·2013-06-10 20:21:44
115 microC through 2 microf capacitor on the right, 190 microC through the middle and 305 microC through 2 microf capacitor on the left loop
229
Dwijaraj Paul Chowdhury
·2013-06-11 01:37:54
Qleft= 190 μC
Qmiddle= 520 μC
Qright= -330 μC
150
Shreya Sharma
·2013-06-11 03:34:25
Qleft=305μC
Qmiddle=210μC
Qright=115μC
1161
Akash Anand
·2013-06-11 04:33:23
Correct Answer is:
Charge on 2μF capacitor(left) is: 35 μC
Charge on 4μF capacitor is: 10 μC
Charge on 2μF capacitor(right) is: 25 μC
1161
Akash Anand
·2013-06-11 05:37:57
There is a correction in the question, please check it again, it should be 20V in place of 200V
150
Shreya Sharma
·2013-06-11 07:09:09
For capacitor on the left,
The charge is flowing in the same direction
V=15(from 20v)+ 2.5(from 10v) = 17.5V
Q= 17.5*2 = 35μF
For capacitor in the middle,
The charge is flowing in opposite direction
V=5(from 20v)- 2.5(from 10v) = 2.5V
Q=2.5*4 = 10μF
For capacitor on the right,
Again the charge is flowing in the same direction
V=5(from 20v) + 7.5(from 10v) = 12.5V
Q=12.5*2 = 25μF
66
Sourup Nag
·2013-06-11 10:49:55
@Akash sir, if i use the initial data, is then my answers correct? :P Everyone had done that same thing in their first attempt :P