1well this sum is nothing but very lentghty
let charge q1 be given on the innermost plate and a -1 on the outermost
then by repeated application of gauss logic we can get the asnswer i dont wanna solve such a lengthy sum
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I can't solve this problem. It is a bit lengthy. You'll find better stuff at my blog. :P
1u are right but i think there's another way of doing it
in the whole system,the capacitances (like that of spherical capacitor) exist only between three pair of shells
shell A-B ,C-D and E-F and these three capacitances can be easily calculated using the formula for capacitance of spherical capacitor i.e.
C1 = k(abb-a) , C2 = k(cdd-c) , C3 = k(eff-e)
in my view these three capacitance will be in series and thus we can easily calculate the capacitance using series combination formula.
plzz tell if this way is right or not
1
EmInEm
·2011-02-03 02:40:19
here electric filed will be only between Aand B , and then Cand D m, and then E and F
E between AB is onlydue to A , between CD is only due to C , between EF is only due to E
then just find Va - Vb , Vc - Vd, Ve - Vf, and the 3 capa are in series
so i think you are right in post 5
