ok optimus i hav made this thread where u n others can post the method of graphical approach for coordinate
1since i have appeared for JEE this year i can tell u that ruler,compass , protractor are allowed in jee
some o the sums of co-ordinate geometry are too lengthy if we go on putting formulas etc, instead if we draw a graph the sum can be solved in seconds
plot the axis and draw the graph of the given curves and u will get the answers in seconds
62lets see a problem
what is the shortest distance between the points on the circle
x2+y2=9
and
(x-12)2+(y-5)2 = 16
1in the above given sum drwa the the two circles with exact radius and centers and measure the distance shortest distance between them with a ruler.
62oh!
I din realise that
@John..
It is not worth doing it exactly in a graphical method... The graphical method is what can be done by drawing a "rough" graph and still getting the answer :)
112,5 is 13 units away from the origin .. radius of first circle is 3 and the second is 4 so the shortest distance is 13 - (4+3) = 6
11the basic approach to the problem in #3 is that the shortest distance will be between the line joininf the centers-radius of C1 - radius of C2
radius of C1=3
radius of C2=4
distance between the centers is 13
so the shortest distance between the two circles is 6[1]
