The remainder when 19[p]92[/p] is divided by 92 is

The remainder when 1992 is divided by 92 is

a) 41
b) 49
c)32
d)44

2 Answers

1
Ricky ·

The idea is that , 19 f ( p ) = 1 ( mod 92 ) , where f ( p ) represents Euler's totient function , i . e , it caculates the number of co - prime numbers less than or equal to p . Its value is , in this case ---

f ( P ) = 92 ( 1 - 1 / 2 ) ( 1 - 1 / 23 ) = 44

So , 19 44 = 1 ( mod 92 )

or , 1 9 88 = 1 ( mod 92 )

So , 19 92 = 19 4 ( mod 92 ) = 361 2 ( mod 92 ) = ( - 7 ) 2 ( mod 92 ) = 49 ( mod 92 )

1
Rajan kushwaha ·

Chinese Remainder theorem (along with other results).

First note 92= 4 × 23 with gcd(4,23) =1.

Let us call N= 1992.

We will compute, N(mod 4) and N (mod 23) and then use CRT tocompute N (mod 92).

First, N (mod 4) = (19)92( 𝑚𝑜𝑑 4) = (−1)92(𝑚𝑜𝑑 4) = 1and 𝑁(𝑚𝑜𝑑 23) = 194.[(19)22 (𝑚𝑜𝑑 23)]2(𝑚𝑜𝑑 23) = (−4)4(𝑚𝑜𝑑 23) = (16)4(𝑚𝑜𝑑 23) = (−7)2(𝑚𝑜𝑑 23) = 49(𝑚𝑜𝑑 23) = 3.

Note in the above we have used Fermat’s Little Theorem.

Now, If you know CRT,

you candirectly say 𝑁( 𝑚𝑜𝑑 92) = 49.

If not, you can compute it.

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