Probability in knockout tournament .....................................
IIT JEE 2015 Forum
›
Mathematics questions
›
Probability in knockout tournament .....................................
64 players play in a knockout tournament. Assuming all players are of equal strength, probabilty that P1 loses to P2 and P3 becomes eventual winner is?
#Mathematics
UP
0
DOWN
0
0
0
Post on Facebook
Post anonymously?
Be the first to Answer
Basic
Integral
Calculus
Operators
Symbols
Matrix
Cases
√
^{}
√


{
}
[
]
(
)
→
~
^
x
^{}
x
_{}
x
^{}
_{}
→
→
ln
log
lg
lim
lim
_{}
cos
sin
tan
cot
arcsin
arccos
arctan
∫
∫
_{}
∫
^{}
∫
_{}
^{}
∫
_{}
^{}
∬
∬
_{}
∬
^{}
∬
_{}
^{}
∬
_{}
^{}
∭
∭
_{}
∭
^{}
∭
_{}
^{}
∭
_{}
^{}
⨌
⨌
_{}
⨌
^{}
⨌
_{}
^{}
⨌
_{}
^{}
∑
∑
_{}
∑
^{}
∑
_{}
^{}
∑
_{}
^{}
∮
∮
_{}
∮
^{}
∮
_{}
^{}
∮
_{}
^{}
∏
∏
_{}
∏
^{}
∏
_{}
^{}
∏
_{}
^{}
∐
∐
_{}
∐
^{}
∐
_{}
^{}
∐
_{}
^{}
+

×
÷
±
∓
=
∪
∩
≠
∼
≈
∅
∀
∃
∈
∋
∝
≤
≥
≃
≅
≡
<
>
≪
≫
⊂
∉
⊃
⊆
⊇
⇒
⇐
⇔
⇒
⇐
⇔
⇑
⇓
⇕
→
←
↔
→
←
↔
↑
↓
↕
↖
↗
↘
↙
↪
↩
⇀
↼
⇁
↽
°
∂
∞
α
β
γ
δ
θ
λ
μ
ν
ξ
π
ρ
σ
φ
ω
ε
ƒ
κ
τ
υ
Γ
Δ
Λ
Σ
Π
Ω
1x2
1x3
1x4
1x5
1x6
1x7
2x1
2x2
2x3
2x4
2x5
2x6
2x7
3x1
3x2
3x3
3x4
3x5
3x6
3x7
4x1
4x2
4x3
4x4
4x5
4x6
4x7
5x1
5x2
5x3
5x4
5x5
5x6
5x8
6x1
6x2
6x3
6x4
6x5
6x6
6x7
7x1
7x2
7x3
7x4
7x5
7x6
7x7
1x2
1x3
1x4
1x5
1x6
1x7
2x1
2x2
2x3
2x4
2x5
2x6
2x7
3x1
3x2
3x3
3x4
3x5
3x6
3x7
4x1
4x2
4x3
4x4
4x5
4x6
4x7
5x1
5x2
5x3
5x4
5x5
5x6
5x8
6x1
6x2
6x3
6x4
6x5
6x6
6x7
7x1
7x2
7x3
7x4
7x5
7x6
7x7
H
Post on Facebook
Anonymous Answer?
✕
Add Image
From Url
or
Upload from Computer
JPG, GIF or PNG only, Max size: 2MB
Tip: Resize your image before uploading
Asked by
Anonymous
20190318 01:25:01
Similar Questions
The remainder when 19[p]92[/p] is divided by 92 is
congruences
Parabola from 'ARIHAN't
Probability in knockout tournament .....................................
Find the length of OA
arithmetic
a challenge for targetiitians
Objective question in Circle
Prove the range for tan3x/tanx is 3 and 1/3
Objective question in Functions
AcadBlock
Questions
Newest
Frequent
Unanswered
Popular
Login
Signup
✕
Login with Facebook
Login with Google
or
Sign Up with Email
Sign up
Full Name
Email
Password
By clicking "Sign Up" you indicate that you have read and agree to the
Terms of Service
.
Cancel
Login
Remember Me
Forgot Password?
Ask Question
Close [X]