equation

waiting for the answer

bhaiya,
can u plz see ur mail box

sorry...jagaran...for the comments....but at least u should've put ur heart & soul into the sum. It makes things better.

Well the 2nd one.....I'm finding 2 solns.

2logx=xlog2

xlog x = 2log 2

Now, by comparing we can easily say,...that one val. is 2.

Next, try this :

log 4 = 2 log2
Now to equate lhs with rhs there should be a 2x2 in the numerator.
Hence, 4 is satisfied.
now, with 3 and so on it is not working as :

suppose log 3² is denominator....then for numerator...
there must be 3x2=6 which is less than 3²

For further values , numerator is constantly decreasing w.r.t val. of x in the denominator.

Hence it's coming to 2,4....and i'm an idiot that I can't find the 3rd soln.

By the way sorry for saying it easy but... which chapter's question is this ?

Here is the link....
http://www.targetiit.com/iit-jee-forum/posts/solve-197.html

Nice explaination by Abhishek Priyam

the graph will intersect at three places hence three solutions....sorry i had misjudged the question at first galnce

want to make one thing clear i had no clue about the first question someone shouldn't call it 'easy' people are here to help others and be helped

hint --- one solution is 4 prove it atleast

12 = sin 30°
√32=cos 30°

sin²30° + cos²30° = 1

Hence x= 2

hey r u there

second one the so called "easy one"

@ arshad what about the other two solutions find them

@ arshad show the steps no trials and errors it has three solutions

@aveek was it easy??? then solve this(without trial and error method)

x²=2^x