Atomic Structure

Which od the following statement is correct for the hybrid orbitals

(A) s + py + pz---->sp2 orbitals lie in the xy plane

(B) ns + np3 + nd2 -----> results octahedral geometry of sp3d2 hybrid orbitals

(C) None

(D) All

11 Answers

29
govind ·

the answer shud be B

49
Subhomoy Bakshi ·

why not all???i.e (D)???[2][1][3]

29
govind ·

option 1 is false
the orbitals will lie in the yz plane..

49
Subhomoy Bakshi ·

so wat it pure depends on user how he names the p orbitals...it is his discretion to name anyone px,pyor pz isnt it??so???or am i wrong??is there any convention for iitjee???plzz reply soon

49
Subhomoy Bakshi ·

wat govind???verify....

29
govind ·

there is a rule in naming the orbitals
for m=0 it shud be pz
and for m= +1 or -1 it can be px or py it depends on the user...
i dont think that pz lies in the xy plane..

49
Subhomoy Bakshi ·

still nt very much convinced with the answer...akari can u possibly help.....think in terms of mathematics...naming is no matter...i can name any of the axes as x y or z...unless there is some fixed jee convention tho!![2]

akari can u help???or qwerty u??

1
Avinav Prakash ·

ans = b

49
Subhomoy Bakshi ·

woh ti mujhe bhi pata hai....but explain why is it not a??

106
Asish Mahapatra ·

it is given naa. we are talking abt the sp2 hybrid orbitals that are formed from s, pz and py hence it is obvious that it will lie in the y-z plane only..

(as the question mentions to consider py and pz)

It is true that m=0 is given for pz and ±1 can be given to any of px and py

49
Subhomoy Bakshi ·

ohh sry overlooked the q....i thot tht it says sp2 hyn can be 4med by s py n pz.. sry all due my gadhaness...[3][3][3]

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