11Yes. The typo is that there will be ammonium-tri-iodode in place of the 2nd thalium tri-iodide.
Govind give the nas finally to the 2nd qsn. Mind u we've to get the wrong statements.
1st one is str8 from NCERT. 2nd one is from MTG.
1) Which of the following will dissolve in a mixture of NaOH And H2O2 ?
a) Ferric Hydroxide b) Chromic Hydroxide c) Aluminium Hydroxide d) Zinc Hydroxide
2) Select the wrong statements -
a) Boron atom in the icosahedron has 5 other B atoms bonded to it, while C in diamond has only 4 nearest neighbours.
b) Thalium Tri-iodide is isomorphous with Thallium Tri-iodide.
c) In nitration mixture, Nitric Acid behaves as a base, and Vant-Hoff factor for nitration mixture is 4.
d) Dipole moment of CH3F>CH3Cl.
Both are multi-correct type.
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6 Answers
29Ans 2 ..first statement is true..
looks like u did some typo in the second statement..i am unable to make out the difference between Thalium Tri-iodide and Thallium Tri-iodide except that 'l' ....no prob...in Thallium Tri-iodide Thallium is in +1 oxidation state and Iodine exits as I3- ...so it is isomorphous with CsI3 and NH4I3..
now the third statement is true..
HNO2 + 2H2SO4 → NO2+ + H3O+ + 2HSO4-... so van't Hoff factor is 4...actually i = ≈3.82 in this case
the fourth statement is false...wanna now how..u can see NCERT alkyl halides chapter..
1129For the second question..only statement D is false...rest are true...
29About Ur First question i dont think that it's straight from NCERT....
I think that the answer shud be C and D as Al and Zn have amphoteric oxides and can form soluble salts with excess NaOH....
That's wat i think..maybe it's right..
11) 2NaOH + H2O2 → Na2O2 + 2 H2O
Na2O2 + Cr(OH)3 → Na2CrO4 + H2O.
Actually , as H2O2 is available , its sure to be involved in some redox reactions. so, its surely not c and d. and a relevant reaction is not possible for a).
