1% ionic character of A-B bond=16(xa-xb)+3.5(xa-xb)2
=16*2+3.5*4
=46
The Electronegativity of 2 elements A and B are 2,4 Whats the % ionic character of A-B bond
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8 Answers
1dude, when the electronegativity difference of two bonds is ( 1.7 - 1.8 ) , it denotes to 50 % ionic
character. if the electronegativity difference is more thn this, then ionic character predominates.
here , the electronegativity difference is 2. thus A-B bond has dominant ionic character.
11abhi, r u sure of wht u hv written ? i think the %age would be well above 50 !
24ya abhishek sahoo...
tahts how it is given in RSM...
but can u or aieeee explain the formula ????
106yup thats the formula for %age ionic character
its der in JD LEE as well
although ive wondered abt its correctness bcz it gives erroneous answers
24anyone with its derivation ???
and is hter any name of this formula ???