mtg

1. When XeF2 and AsF3 react and form adduct,the hybridisation of Xe and As in adduct are respectively ________,_______ ??

2. When DEVARDA's alooy is treated with nitrates in the presence of alkali the gas evolved is
(a) NO
(b) NO2
(c) NH3
(d) N2O

3. Which of the following will dissolve in a mixture of NaOH and H2O2 ?
(a) Fe(OH)3
(b) Cr(OH)3
(C) Al(OH)3
(d) Zn(OH)2

4. The pair of compounds which cannot exist together in aqueous solution is
a. Na2CO3 and NaHCO3
b. NaHCO3 and NaOH
c. NaOH and Na2HPO4
d. NaOH and Na2HPO3

3 Answers

11
Tush Watts ·

Ans 2) (c)

3 Cu + 8 HNO3 → 2 NO + Cu (NO3)2 + H2O

Devarda 's alloy (Cu / Al / Zn) + NaOH → H

NO3 - + 9H → NH3 + 3 H2O

Ans 3) (d) ... [Not sure]

29
govind ·

ans 1
XeF2 + AsF3 → [XeF]+ [AsF4]-
so hybridisation of Xe is sp3 and hybridisation of As is sp3d
in ans 4 i think the answer shud be b and c ..because NaOH is a very strong base and it will react with salt if there is acidic hydrogen present in it..

11
Gone.. ·

1. sp3,sp3d2
2. C
3. B,C,D
4. B,C,D

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