OXIDATION NUMBER..

JEE Advanced Coaching › Inorganic Chemistry questions › OXIDATION NUMBER..

WHAT IS THE OXIDATION NUMBER OF CHROMIUM IN [Cr (O2)4]

PLZ SOMEONE REPLY..

THE OXIDATION NO FOR EACH O IN (O2) IS -2??????

#Chemistry #Inorganic Chemistry

UP 0 DOWN 0 0 7
Post on FacebookPost anonymously?

7 Answers

1

Vinay Arya ·2011-02-10 07:01:00

I think you have mistyped somewhere.or the question is wrong.How can it have oxidation state to be +16?

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

seoni ·2011-02-10 07:18:52

+4?

pl confirm...

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

bhaarat ·2011-02-10 07:24:36

i"m sorry it is K3{Cr(O2)4} THE ANSWER GIVEN IS +13 BUT HOW IS THAT POSSIBLE ???

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

Vinay Arya ·2011-02-10 21:35:14

To send Cr to such a high oxidation state too much huge amount of energy is required,which is not possible.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

seoni ·2011-02-11 00:58:55

source pls?

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

bhaarat ·2011-02-13 07:47:41

ARIHANT INORGANIC CHEMISTRY...

UP 0 DOWN 0
Post on FacebookPost anonymously?

23

qwerty ·2011-02-13 08:23:06

Cr is in +5 here. All Oxygen are involved in peroxy linkage , i.e each O has ON= -1 ..

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω