241) violet ???
1. In the manufacture of glass,addition of MnO2 gives
A.Yellow colour.
B.Red colour
C.Violet colour
D.Pink colour
2. When iodine reacts with NaF,NaBr and NaCl
A. It gives mixture of F2,Cl2,Br2
B. gives Cl2
C. It gives Br2
D. None of the above
3. Identify the correct order of solubility of Na2S,CuS,ZnS in aqueous medium
A. CuS>ZnS>Na2S
B. ZnS>Na2S>CuS
C. Na2S>CuS>ZnS
D. Na2S>ZnS>CuS
4. On boiling an aqueous solution of KClO3 with iodine,the product formed is
A. KIO3
B. KClO4
C. KIO4
D. KCl
5. Among the fluorides given below which will further react with F2 ?
A. NaF
B. CaF2
C. SF6
D. IF5
-
UP 0 DOWN 0 0 9
9 Answers
116. HBr and HI reduce sulphuric acid,HCl can reduce KMnO4 and HF can reduces
A. H2SO2
B. KMnO4
C. K2Cr2O7
D. None of the above
7. The ion which cannot undergo disproportionation is
A. ClO4-
B. ClO3-
C. ClO2-
D. ClO-
12) I2 can't oxidise F- , Cl- and Br- . this follows frm the result dat the lower element ( in molecular state) in Gr-17 can't oxidise its higher element in the group ( in ionic state ).
F- can't be oxidised by I2 , Cl2 or Br2.similarly , Cl- can't be oxidised by Cl2 or Br2 and Br- can't be by I2.
3) judjed on the basis of lattice energy. more lattice energy cn overcome the hydration energy of the compound to enhance its solubility.
4) actually, KClO3 will be oxidised by I2, thus either KClO4 or KIO4 cn be formed. if we consider a transition reaction then KClO3 disproportionates into KCl and KClO4 and on reaction wid I2 ,the displacement rkn takes place forming KIO4.
5) as eure said , IF7 cn be formed. also , none of the other elements given in the options cn be furthur oxidised.
6) as the bond strength of HF is too high to break and F- is very hard to be oxidised.
7) ClO4- is the most stable among the four options given.