Given v=a√x
or (dx)/(dt)=a√x
or x^{1/2}dx=adt
Integrating the above equation we get
2x^{1/2}=at + K.
Now at x=0 at t=0.So K=0.
So the required relation is 2x^{1/2}=at
A particle located at x=o at time t=0 starts moving along the positive Xdirection with a velocity v that varies with time is? explain

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3 Answers
Swarna Kamal Dhyawala
·20140627 03:56:47
A particle located at x = 0 at time t = 0, starts moving along the positive xdirection with a velocity
â€˜vâ€™ that varies as v= a√x . The displacement of the particle varies with time as
Sushovan Halder
·20140627 08:00:21