AITS Physics Tricky

The Figure shows two rods BC and OA hinged from B and O respectively. Rod BC has a groove in which A of rod OA can slide smoothly. At a given instant,the rod BC has an angular velocity ω. The speed of end A of the rod OA at this instant will be

(A) ωl
(B) 2ωl
(C) 3ωl
(D) None of these

I simply couldnt understand the question.. Please help me figure out this problem.....

11 Answers

62
Lokesh Verma ·

aree u sure both these lenghts are L

if that is the case the diagram should have been an isoceles triangle..

as i see it the asnwer is either 2wl or none of these..

The component of the velocity of A in the Y direction is given.. we know that A moves perpendicular to the Rod OA.. so u have a hint?

1
Rohan Ghosh ·

i got answer as 2wl

and yes the figure should be an isoceles triangle

33
Abhishek Priyam ·

CAn u plz say just few point on it....how to proceed

yahi hai jo nahi bana :P

62
Lokesh Verma ·

see what is the direction of motion of A..

and what is the direction in which u know the velocity of A..

What is the angles between thse directions

ab ho jaega :)

33
Abhishek Priyam ·

Ok let me see...

33
Abhishek Priyam ·

Uff ab ban gaya figure hi ganda tha paper me.
i didn't saw that its equilateral triangle

jada time chemistry me hi de diye the :(

9
Celestine preetham ·

this problem is solved by making a LOT of wrong assumptions
fiitjee gives such confusing probs in the name of innovating new ones
dont worry iitjee will test ur correct concepts

edit

sorry after seeing rohans elegant sol
i feel i was mislead by the dia
ne way my fault to misread
its a real good q if dia was proper

62
Lokesh Verma ·

I thiought this was a very conceptual quesiton.. serioiusly!

1
Siddharth ·

Rohan tell us how u did it....

1
Rohan Ghosh ·

see one thing is known

the rod's length cant change
so the velocity of A can only be in the perpendicular direction of OA

let angle √OAB=θ
then AB=2Lcosθ

so velocity of A in perpendicular direction =2Lcosθw

let velocity of A belonging to OA =v
so we get vcosθ=2wLcosθ (as they are both along the perpendicular and the same)

so v=2wL

1
Siddharth ·

Ohhh cool
Thanks a lot..

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