BERNOLIiiiiiii

This type's been hauntin me .........

I know its sumthiing to do wid ∫

pl. help

11 Answers

21
tapanmast Vora ·

Is dis eqtn crrct :

A∂H/∂t = a√2gh - α

33
Abhishek Priyam ·

just a minus sign is required.

answer it think will be (d)

21
tapanmast Vora ·

I dont hav da answer Buddy [2]

but wat u get has to be rite !!!

33
Abhishek Priyam ·

are nahi.. bas dH/dt=0 kiye... :P

1
gsns gannavarapu ·

hey can u post d workin plzzz......

21
tapanmast Vora ·

OH!!!!! ye to khoda pahad aur nikla chuha........ [3]

Chalo lets modify the Q a bit..........

If it wer Asked height after time t, we wud ∫ the DE I wrote in #2 write/wrong ??

wat was that - sign u wer tokin abt........

33
Abhishek Priyam ·

@tapan
Adh/dt=α-a√2gh
yes you have to solve this..

@gsns
dH/dt=0

so we can get h=α2/2ga2

21
tapanmast Vora ·

oh u wer tokin of this minus sign ..........

but That depends on wether ur dH is Rise in ht. or fall

33
Abhishek Priyam ·

:P

haan...

3
iitimcomin ·

keep this in mind at Hmax .... volme of water comin in per sec = volume water goin out per sec

3
iitimcomin ·

let max lev. be H ,,

a√2gH = alpha

H = ALPHA^2/2ga^2

Your Answer

Close [X]