1but why verticle component of velocity of C.O.M will be constant
A particle of mass 2m is projected at an angle of 45 degree with the horizontal with a velocity of 20√2 m/s. After 1 sec, explosion takes place and the particle is broken into two equal pieces. As a result of explosion one part comes to rest. Find the maximum height attained by the other part
-
UP 0 DOWN 0 0 5
5 Answers
62the vertical component initially is 20m/s
after 1 second,
it becomes 20-10.1= 10m/s
then it explodes in 2.. one comes to rest.. thus new velocity becomes 20m/s (vertical compononet again!)
So the max height from this time it can travel is 202/2.10=20m
In the 1st second it travelled 15 m..
total will be 35 m
see calculation errorrs.. :)
1
33No the vertical component of velocity is not constant... at the instant after 1 sec it is 10ms-1. So after explosion also (same instant) velocity of second part should be such as that to make vcom=10 ms-1 (at that instant). So 20 ms-1
62yup... the vertical compoent became 20 again.. (i did not mention it.. but you can see the line above
So the max height from this time it can travel is 202/2.10=20m