1i approached in the same way. but wat next
1.A particle of mass m1 collides elastically with a stationary particles of mass m2 (m1>m2). Find the maximum angle through which the striking particle may deviate as a result of collision.
2. A shell flying with velocity u burst into three identical fragments so that the kinetic energy of the system increases by n times. What maximum velocity can one of the fragment obtain.
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16 Answers
49well solving the equations that i have got will kill me !!!!!
neways my method:
1)
m1v1sinα=m2v2sinβ
m1v=m1v1cosα+m2v2cosβ
e=√(v1sinα+v2sinβ)2+(v1cosα-v2cosβ)2v
and e=1
we have to maximise α for various values of β
49let mass be 3m
initial energy=32mu2
final energy=3n2mu2
v12+v22+v32=3nu2
v1+v2+v3=u
bold letters signify vectors...
1irodov ka solution ho to dekh ke post kar na.
waise results ko yaad kar ke bhi kaam chalaya ja sakta.
49no i dont have irodov soln..
ek kaam kar temme the problem number and page no
kal school jaa kar check kar lunga! :)
1problem 1.171 and 1.176
by the vivek agar ek bar solution download kar liya to sare conecept ki aisi ki taisi ho jayegi
106i think Q1 was solved way back here on tiit. ... the answer was arcsin(m2/m1) ..
priyam asked that question
it was solved by me as well as atgs
1ans 1 - sin(theta) = m2/m1
2 - highest velocity is 2u
vivek may be ur edition is different
71I'm having the Arihant Published one. I mean it's republished in India by Arihant. Cost 75!