3sunil watz da answer!!!!!!!!!!!!!!!!!!
A solid cylinder of mass m is placed on a rough horizontal surface and a spring of stiffness k is connected to the point A at the same level as the centre O of the cylinder.
OA and OB lie in a plane perpendicular to the axis of the cylinder.
In the equilibrium position, the spring is at its natural length.
1. The cylinder is given a small displacement and it is found to perform oscillations without slipping. The angular frequency of these oscillations are????
2.The cylinder is allowed to oscillate while rolling and its amplitude is increased till it is on the verge of slipping. The maximum potential energy, stored in the spring during the motion equals 1/9th of the energy stored, were the cylinder to be suspended by it in equilibrium. The coefficient of static friction, μ, between the cylinder and the plane equals???
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30 Answers
3im gettin a very simple answer..............................
w=√k/m....................
many of u above hav neglected frictional force!!!!!!!!!!!
11Has anyone of u has got the answer??
And please do explain how do got that......
33bhula gaye the yaha [ 3 ] chalta hai..
[:P] nahi ... orkuttin habbit.. [3]
1woh bhi yahan batana tha...
btw, i realised jus now....
aur aits dene ke baad main hamesha ulta-sidha bakti hun [3]
33its cylinder.. solid one...
and if its sphere then it is wrong then also.. u have to take about point of contact not about COM..
1main aise hi ... sochi ...
chhoro force hi achha hai...
k(Rθ)R=- 2/3mR2 d2θ/dt2
=> kθ =- 2/3mα
=> α = -3k/2m θ
so w2 = 3k/2m
