Friction-2

5 Answers

996
Swarna Kamal Dhyawala ·

F = (8 x 10 x 0.42 + 2 x 10 x 0.42 + 6 x 1.5) N
F = 51 N

466
Himanshu Giria ·

13.2

150
Shreya Sharma ·

17.2 N

1161
Akash Anand ·

Answer is 51N

481
Anurag Ghosh ·

1st equation-f1=0.42*2*10=8.4N
2nd equation-F=f1+f2+6a[where f1 is d friction bet. the 2kg and 6kg block and f2 is d friction bet. 6kg and the surface and a is the acc. with which the 6kg block is to be pulled out]
f2=0.42*10*8=33.6N
F=8.4+33.6+6*1.5=51N

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