friction problem

HC VERMA Friction 28

38 Answers

62
Lokesh Verma ·

See if this fbd helps!

the small block m is moving with the same horizontal velocity as the larger mass M
And M has no vertical velocity. While m has. This clearly says that the relative motino is along surface...

11
Subash ·

@priyam ans is wrong now what

1
skygirl ·

yup same equations ...

i mean force equations...

and am very sorry about the constraint eqn...

it will be -a1+2a2 = 0 ..

11
Subash ·

but still i am not getting the answer

1
skygirl ·

is it?
okie lemme try.........

1
skygirl ·

i think there sumthnng wrong.....

62
Lokesh Verma ·

sankara!!! NO!! :O

It oppsosed relative motion of the surface of contacts!!!!

How did u manage to find the relative motion of the surfaces in that direction! :O

3
msp ·

sir doesnt the contact surface of M is moving horizontally

62
Lokesh Verma ·

it does.. but then is the relative motion between M and m in the direction u have shown!?

3
msp ·

sir can u please give me the vector formof the frictional force

33
Abhishek Priyam ·

Made some edits above in second equation

11
Subash ·

Is the tensional force due to the upper pulley on the massM acting both downwards and sideways

62
Lokesh Verma ·

yup..

11
Subash ·

These are my equations

R=T+Mg+f1
2T-N-n2(T+f1+Mg)=2Ma

mg-T-n1N=ma
N=2ma

11
Subash ·

Are these equations rite . i dont feel so because i hav taken static friction for both i am not sure but i could not write any other eqn

33
Abhishek Priyam ·

Lol...

i am a fool my eqn were 105% wrong :(

62
Lokesh Verma ·

subash have u taken the wrong values of a and 2a..

I think that the vertical acceleration will be 2a .. while the horizontal will be a each :)

11
Subash ·

identified my mistake thnx bhaiyya

1
kIrTi kUmAr kAsAt ·

http://www.physicsfundas.com/hcvermasolutions/06.SOLUTIONS%20TO%20CONCEPTS.pdf

find the full solution to ur problem here!!!!

11
Subash ·

@ sky girl Doesnt the frictional force between the blocks act on M too?
why dint you take it into account

11
Subash ·

Find the acceleration of mass M in the situation. The coefficient of friction between the blocks is n1 and that between the bigger block and the ground is n2

11
Subash ·

please bear with the bad quality of the image

3
msp ·

use the relation a1+a22=0

u will have two eqn for the two bodies.solve these three eqns to get the final ans.

where a2 is the horizontal acc of the blockM

3
msp ·

reply if i was wrong with my constraint relation

1
skygirl ·

constraint is ok..

but y tensions are diff.. ?? tension will same only...

3
msp ·

hey sky l1,l2,l3 are the lengths of the part not the tension

1
skygirl ·

1
skygirl ·

@sankara.. i was mistaken.. dats length... then its okie... :)
am sorry.. :(

11
Subash ·

sky girl is a=a2

3
msp ·

post ur question if there is diagram in that question post with ur diag also.

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