Gravitation

Let V and E denote Gravitational Potential and Gravitational field at a point.
Is it possible to have V=0 but E≠0 ?

7 Answers

1
Bicchuram Aveek ·

E = - dV/dr

if E is not = 0 V can never be equal to 0.

So above statement is impossible.

23
qwerty ·

aveek i didnt get ur logic , if a curve has no point of extremum, why cant it be zero? [eg: f(x)=x has no point of extremum but it is zero at some x ]

btw wat if i choose an arbitrary point as zero potential which has a nonzero electric field ??????
suppose i choose the potential at the earth's surface to be zero. Clearly electric field isnt zero.
so it is possible

1
swordfish ·

@Qwerty
But if we proceed with the equation i.e.
E = -dv/dr

Here if we put V=0 then E must be 0 as derivative of 0 is 0.

I guess you meant 'gravitational field'.

1
spidey timon ·

i agree with qwerty potential at a point depends on the reference we choose

23
qwerty ·

@Swordfish: wats d derivative of f(x)=x at x =0??

1357
Manish Shankar ·

Yes take the simple case

V=10x
E=10 i

at x=0 V=0

1
swordfish ·

Thanks everyone. I got it.

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