1
Anirudh Kumar
·2010-03-01 19:58:11
no. of fissions = 104/200*1.6*10-19*106
= 3.12*1014
what's the answer?
1
Manmay kumar Mohanty
·2010-03-01 20:04:25
anirudh yaar 200 MeV is given but u took only 200 eV in the denominator.
u have to take 200 x 10 6
Also probably one fission gives 3 neutrons, and each is capable of further fissions and emits 9 more neutrons(3 each ).
so may be ans will be different....
1
Anirudh Kumar
·2010-03-01 20:06:53
hey man may saw that and corrected.
can't say anything about the fission to be controlled or not?
let akshay post the answer
1
Manmay kumar Mohanty
·2010-03-01 20:08:56
may be but if the ans varies my reason will into highlight......
HOPE UR IS CORRECT (seems to be)
1
akshay sharma
·2010-03-15 11:15:49
m so sorrrrryyyyyyy guys i had forgotten to post the answer ............
yups answr is 3.12*10^14 fissions per secnd.......
plz forgive me
nd thank ew so much friends to try this prblem.......