3sorry my calc. mistake ...............took 4*4 = 64 .....[3]
a syringe of diameter D=8mm and having a nozzle of diameter d=2 mm is placed horizontally at a height of 1.25m as shown in the figure.
An incompressible and non viscous liquid is filled in syringe and the piston is moved at speed of 0.25 m/s .
Find the range of liquid jet on the ground.
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UP 0 DOWN 0 0 6
6 Answers
3AV = av
V = av/A
0.25 A/a = v
0.25(16) = v edited 64->16 [calc error]
4 = v 1
4√2(1.25)/g = 4√0.25 = 2
11AV =av
4*4*0.25 = 1 * v
v = 4m/s
S = gt2/2
1.25*2 = 10t2
2.5 = 10t2
25/100 = t2
t = 5/10
t = 0.5 secs
x = 4 * 0.5
Range = 2m