Kinematics

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A body of mass 10 kg is being acted upon by a force 3t²and an opposing constant force of 32N.The initial speed is 10ms^-1.The velocity of body after 5s is
(a)14.5ms^-1 (b)6.5ms^-1 (c)3.5ms^-1 (d)4.5ms^-1
(According to me,
acceleration of the body=Fm=3t²-3210
velocity=âˆ«3t²-3210=t³10-32t10
At t=5s,
v=12.5-16=-3.5ms^-1.....but the correct answer given is (b).......)

#Physics #Mechanics

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2 Answers

21

mohit_ sharma ·2012-06-06 04:45:47

₁₀^vâˆ«dv = ₀⁵âˆ«(3t²-3210)dt

evaluating this v=6.5 ms^-1

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158

Anik Chatterjee ·2012-06-07 03:15:26

ya...got it...thanks...

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