1161
Hamza-Ul-Huda the acc of block A would be g/7 upward
acc of block B would be 2g/7 downward
but in option A it is reciprocal it should be
g/7 upward 2g/7 downward
d) none of theseHamza-Ul-Huda m i ri8 sir??
466A → T → x
B → 2T → y
Tx + 2Ty = 0
x+2y =0
a1 = -2a2 .......( i )
T - 4g = 4a1 .......( ii )
T - 5g = 5a2 .......( iii )
Solving we get :
a1 = -2g / 7
and a2 = g / 7
Aditya Agarwal that will be 5g - 2T = 5a2Akash Anand Wrong Solution....try again Himanshu Giria equN (iii) is actually 2T - 5g = 5a2
49Let the acceleration for block A be a1 downwards and that for B be a2 upwards.
so,A→T→-x
B→2T→Y
-Tx+2Ty=0
x=2y
a1=2a2
now,4g-T=4a1
8g-2T=8a1=8(2a2)=16a2....(1)
2T-5g=a2....(2)
(1)+(2)
3g=17a2
a2=3g/17
a1=6g/17
SO THE ANSWER SHOULD BE NONE OF THIS i.e. (D)
Himanshu Giria I could not find any mistake in this but plz tell the mistake in my ans
Himanshu Giria I took both the accln s. In upward direction
Himanshu Giria So how wud the ans cm diffrent
Swarna Kamal Dhyawala @pratyasha i think there is mistake in equation (2) it shud be
2T-5g = 5a1535accln A = g/9 downward
accln B = g/18 upward
Pratyasha Das @swarna kamal my mistake ...the ans is a
