**486**
Niraj kumar Jha
**·**2013-07-15 08:38:43
acc. of m2 g/3 downward.

acc. of m1 g/3 upward.

acc. of M 2g/3 rightward.

tension in the joining m1&m2 is 4g/3

**1123**
Sourish Ghosh
**·**2013-07-17 07:31:42
m2 = g/3 down

m1 = g/3 up and 4g/15 right

M = 4g/15 right

T = 4g/3

**1163**
Akash Anand
**·**2013-07-17 23:53:56
All of you have got the wrong answer. This is a very conceptual question of Constraint Relation. All I can give you is a hint for now. Acceleration of 2 kg block and 1 kg block in vertical direction will not be the same (in magnitude). If we take acceleration of 1 kg block as a1 (in upward direction) and acc. of 2 kg as a2 (downward) and acc. of 4 kg as a3 in rightward then constraint relation will be: a2=a1+a3 (Think why??)

**996**
Swarna Kamal Dhyawala
**·**2013-07-18 08:44:36
a_{1}=107 m/s^{2} (for block of mass 1kg)

a_{2}=307 m/s^{2} (for block of mass 2kg)

a_{3}=207 m/s^{2} (for block of mass 4kg)

T=807N

**51**
Aniq Ur Rahman
**·**2013-07-19 04:12:03
Are the F.B.Ds correct.

I'm having difficulty in finding the constraint relation .

**51**
Aniq Ur Rahman
**·**2013-07-19 04:12:48
Are the F.B.Ds correct?

I'm having difficulty in finding the constraint relation .

·0·Reply·2013-07-15 17:14:23