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find the minimum value of μ between the two blocks for no slipping

9 Answers

13
Двҥїяuρ now in medical c ·

options[12]

106
Asish Mahapatra ·

As there is no slipping, consider the block of mass m,
F-μmg = ma ....(i)
μmg=2ma ....(ii)
So, a=μg/2
Putting in (i),
F=3μmg/2
==> μmin = 2F/3mg

..........i am not sure abt my process but do verify.

24
eureka123 ·

aA+B=F/3m
=>aA=F/3m
Force eqn for upper block (A)

F-f=maA
=>F-f=F/3
=>f=2F/3 ≤ fmax
=>F≤3μmg/2

24
eureka123 ·

oops...........sorry ashish din see ur post.......[3]

62
Lokesh Verma ·

I like eureka's method more :)

Good work both of you.

24
eureka123 ·

thank u sir.......[6]

1
big looser ......... ·


don't u think that ther will be a force acting on bigger block through string

106
Asish Mahapatra ·

yes, it definitely will but see the attached FBD
there will be in all 4 forces by the string.... as u can see from FBD, all 4 cancel each other.

1
big looser ......... ·

thanks everyone

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