simple sum v^2=4as/m here v is speed and s is the distance and tangential force is dv/dt where v is speed P.S. i wrote this as i always get confused between speed and vel
The kinetic enegry of a particle moving along a circle of radius R depends on the distance covered a T=as^{2},where a is a constant.Find the force acting on the particle as a function s.

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3 Answers
Hint: there are two componnents of acceleration..
One towards the center another tangentially..
The vector sum will give the resultant acceleration.
Hence find the force.
At the instant after the system of objects is released, find the accelerations o . ... about an axis passing through its centre and perpendicular to its symmetry axis. ... In the fig. shown a smooth ring is connected to rod AB while rod CD passes thru ring . At the given instant angular vel. of rod AB abt hinge A is 1 rad/s and AC=CB.