# Mechanics Booster-4

1161
Akash Anand ·

1133
Sourish Ghosh ·

a) 5Î¼g3
b) 3w0R11Î¼g
c) 5w0R11Î¼g

• Akash Anand All answers are wrong...try again.
486
Niraj kumar Jha ·

a)Î¼g3
b)3w0R4Î¼g

• Akash Anand Check the second answer again
• Sourish Ghosh I think the 2nd part should be 3/7 instead of 3/4.
• Niraj kumar Jha we should conserve ang. momentum right?
• Niraj kumar Jha is it 9/4for 2nd part
• Akash Anand Sourish is right for the 2nd part.
• Sourish Ghosh Sir, the 3rd part is confusing. It says pure rolling persists after t*. That means after t* the disc will move linearly at a constant speed (are we neglecting friction?) while the block will decelerate (its velocity will change). Now the question says that the block and the disc move together always which implies they will have the same velocity at any instant. How is this possible?
• Soumyadeep Basu Pure rolling does not necessarily mean that linear velocity will remain constant. It just means that v=r.(omega) .
51
Aniq Ur Rahman ·

a) Î¼g3

b) 3Ï‰oRÎ¼g

• Akash Anand Second answer is wrong.
51
Aniq Ur Rahman ·

c) √(65)RÏ‰oÎ¼g

• Akash Anand Wrong ..try again
• Aniq Ur Rahman I guess this is wrong, cuz i applied Conservation of Energy, but energy will be lost due to friction.
• Aniq Ur Rahman I guess this is wrong, cuz i applied Conservation of Energy, but energy will be lost due to friction.
1161
Akash Anand ·

Keep trying ..I want answer of this question from you only.

865

(a) Î¼g3
(b) 3RÏ‰o7Î¼g
(c) RÏ‰o2Î¼g

865

(a) Î¼g3
(b) 3RÏ‰o7Î¼g
(c) RÏ‰o2Î¼g

• Akash Anand Check the last part again :)
• Shaswata Roy Even I got the same answer for the last one.Can we not equate angular momentum at time t :(omega) - 2(mu)gt/R=0 ?Am I missing out something?
1161
Akash Anand ·