mechanics

Centripetal acceleration of a particle of mass m moving in a circular of radius r is 4/r2 . What is the momentum of the particle?

4m/r

4m/√r

2m/√r

2m/r

ans (c)

6 Answers

62
Lokesh Verma ·

v2/r=4/r2

v=2/√r

mv=m.2/√r

which is the momentum

1
MAGIC MATH ROCKS ·

ek aur.......

A thin uniform rod of mass m and length is hinged at the lower end of a level floor and stands vertically. It is now allowed to fall, then its upper end will strike the floor with a velocity given by???????

1
MAGIC MATH ROCKS ·

ohhhhhhh!!!!!!!!!!1

yeAH..... I HAD NEVER THOT OF CONVERTIN IT A TO V2/R

THANKU!! :)

2ND ONE 2 SEEMS EASY

62
Lokesh Verma ·

mgL/2 = 1/2I ω2

I=mL2/3

mgL/2=1/2 mL2/3 ω2

g=L/3 ω2

ωL=√3gL where L is the height of the gate.

1
MAGIC MATH ROCKS ·

oh k.... thnx........

so if v wer askd vel of mid - pt ans wud hav bn .5 *√3gL..... rite??

62
Lokesh Verma ·

yup :)

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