In the arrangement shown in the figure,find the acceleration of M.The pulleys and strings are light!
1i think i got the ans
acc of M = (M-5m)g/(M+15m)...........
1let acceleration M be a & of m be b
see, by equation of constraint u will get
b = 3a
by newtons motion
Mg-2.5T = Ma
2.5T-5mg = mb
where T is tension in rope connecting roof & M
solve & u will get the ans,
one more thing
can u tell me how to use latex in this forum..............
341Are you sure its not g(M-5m)/(M+25m)?
Thats the answer I get.
Logically the minus sign has to be there.
1i m getin same as dimen but prophet frm where dat M+25m come isnt it M+15m
341If the acceleration of M is a, what is the acceleration of m?
You seem to have taken it as 3a. Its 5a.
1********edited
its 5a ......correction
& -ve sign has to be there
3yes the acceleration of m is 5 times that of the acc of M
the eqns are
Mg-(T1+T)=Ma
T-mg=m3a
where T=T1/4
1yes the ans given is correct only..
the constraint eqn is : 5A + a=0 (A= acc of M, a= acc of m)
the force eqns are:
5T-Mg = - MA --- 1
T-mg= -ma ----2
I) now find a and A in terms of T.
II) put in the constarint eq. ... so u will get T.
III) then find a and A from the force equations.. :)
15T-Mg=Ma-----------1
mg-T = 5ma---------2
multiplying eqn 2 wid 5 and thn adding them....we get....5mg- Mg=Ma +25 ma
a=g(5m-M)/M+25m