661vertical component of initial velocity =12m/s(taking g=10m/s2)
it will pass through the ring 1.2s after he releases the ball.
the direction of initial velocity relative to the frame of reference of the flat car=tan-1(3/4) with the horizontal.
he must release the ball at a horizontal distance of 19.2m in front of the ring.
- Shivam Tiwari i think he must release the ball at a horizontal dist of 24m from d ring.........becoz d net horizntl velo of d ball wid resp to ground is 20m/sUpvote·0· Reply ·2013-04-02 06:44:34
Akash Anand For last part Shivam is correct. 24m is the right answer.
Good Work