Projectile Motion

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591

Akshay Ginodia ·2014-01-30 03:40:47

Acc. to the 1st graph V_y becomes zero after 1/2 seconds which happens at the highest point
so half the time of flight = usinÎ¸/g = 1/2
so , usinÎ¸ = g/2 = 5 m/s

similarly at x=2 V_y = 0 ,therefore x=2 is half the range..from there u can get it

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Sahil Jain ohh!!!second graph gives the range...i didnt see that x there
Upvote·0· Reply ·2014-01-30 03:50:14
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591

Akshay Ginodia ·2014-01-29 23:15:37

Y component = 5 m/s
X component = 4m/s

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Sahil Jain how
Upvote·0· Reply ·2014-01-30 03:25:17
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