Δp / (μL/8πr4) = Q : flow rate which is constant ...this is the general equation ..
and the two pipes are connected in series ..
so
Δp / (μL/8πr4 + μL/8π(2r)4) = Q'
→ Δp / (17 μL/8π(2r)4) = Q'
this is same across the first tube so
Δp / (17 μL/8π(2r)4) = Δp' /( μL/8πr4)
Δp' = 16/17 Δp
so the answer is pressure across the 1st tube is 16/17 m of water