rotation

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#Physics #Mechanics

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chinmay ·2009-02-16 23:17:16

IF I TAKE MY REFERENCE AS OUTSIDE SHOULD I CONSIDER PSEUDO FORCE??

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iitimcomin ·2009-02-16 22:56:31

oh sorry thought it waz a sphere ........

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chinmay ·2009-02-16 22:57:23

But in the FBD for the wedge Ma2 acts in the forward direction..

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iitimcomin ·2009-02-16 23:00:59

yes that is the psudo force yaar!!!!!!!!!!which is y im doing summation Fx and Fy = 0 ..........
REREAD PSUDO FORCE CHAPTER!!!!!!!!!!!

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chinmay ·2009-02-16 23:04:35

But why ma1 backward??
I seriously don't understand .
Kindly Explain!!

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iitimcomin ·2009-02-16 23:10:07

YAAR A1 IS FORWARD BUT I AM TAKIN MY FRAME OF REFERENCE INSIDE THE CYLINDER!!!!!!!!!!!!!SO ITS BACKWARD..............EG... IF I SIT IN A BUS ACCN. FORWARD I FEEL FORCE IN BACKWARD DIRECTION!!!!!!!!!!

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iitimcomin ·2009-02-16 23:11:35

IS IT 15(B)....CHECK I WUD HAV MADE MISTAKES IN SOLVIN EQXNS... I ALWAYS DO THAT!!!!

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chinmay ·2009-02-16 23:12:30

yes U r right..

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chinmay ·2009-02-16 23:13:02

will it be wrong ,If I assume a1 forward.

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iitimcomin ·2009-02-16 23:15:38

DEPENDS ON UR FRAME OF REFERENCE........ IVE TAKEN THE FRAME OF REFERENCE AS INSIDE THE CYLINDER .......... SO ITS BACKWARD .... IF I TAKE MY FRAME OF REFERNCE AS OUTSIDE THE SYSTEM ITS FORWARD AS U SAID!!!!!!!SORRY IF I CONFUSED U WITH PSUDO FORCE....... ITS JUST THAT U CAN SOLVE IT EASILY!!!!!!!!!!

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iitimcomin ·2009-02-16 22:55:57

backward direction which is y the psedo force is in the forward dirction!!!!!!!!!

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iitimcomin ·2009-02-16 23:19:19

THEN THERES NO NEED........BUT IT MAKES IT LITTLE MORE COMPLICATED TO SOLVE

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chinmay ·2009-02-16 23:20:22

YES, I UNDERSTAND.THANKS AND SORRY

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iitimcomin ·2009-02-16 23:25:31

HEY Y AR U SORRY!!!!!!!DONT BE!!!!

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Abhishek Priyam ·2009-02-16 23:41:55

IF I TAKE MY REFERENCE AS OUTSIDE SHOULD I CONSIDER PSEUDO FORCE??

For that.. (i personally hate pseudo force...theres many real forces so why introduce a new one... :P)

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chinmay ·2009-02-17 00:08:33

@iitcomin,
do u need the 4th eqn??

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chinmay ·2009-02-17 00:12:42

u there?

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Abhishek Priyam ·2009-02-17 00:18:00

theres no need... its only for reaction from ground...

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chinmay ·2009-02-17 00:21:37

@ priyam
How did u get that constraint eqn.

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Abhishek Priyam ·2009-02-17 00:26:04

acceleration of cylinder and incline perpendicular to plane is same... (1st constraint equation..)

2nd constraint eqn for no slipping..

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chinmay ·2009-02-16 22:47:16

see what's wrong with what I did.

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chinmay ·2009-02-16 22:32:25

It's not fixed

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39

Dr.House ·2009-02-16 22:32:51

he gave wedge is placed on a smooth horizontal floor. so its not fixed............

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chinmay ·2009-02-16 22:33:04

I'll post what I did.
but not getting the final answer that the book has got..

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chinmay ·2009-02-16 22:34:07

physics spectrum

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chinmay ·2009-02-16 22:35:42

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iitimcomin ·2009-02-16 22:41:51

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chinmay ·2009-02-16 22:43:24

Why is the direction of Ma1 backward

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Dr.House ·2009-02-16 22:44:53

because ma2 is rightward.

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chinmay ·2009-02-16 22:46:50

are u telling that the cylinder goes up,
The wedge has an acceleration to the left because the cylinder is movind down.

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω