rotation

AIEEE 2015 Papers › Mechanics questions › rotation

the driving side of a belt has a tension 1600N and the stock side has 400 N tension The belt turns a pulley 40 cm in radius at the rate of 300 r.p.m. to a dynamo The power delivered is

Please give the solution

#Physics #Mechanics

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5 Answers

62

Lokesh Verma ·2009-02-06 01:11:29

this is not in syllabus karan..

it has to do with e^Î¼Î¸

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24

eureka123 ·2009-02-06 10:28:23

Sir I think we can solve it in this way..............so it wont look out of syllabus........
Torque_net=(1600-400)(0.4)=1200(0.4)=480
&& Ï‰=10Ï€ r/s

=>Net power delivered to dynamo=480(10Ï€)=4800Ï€

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62

Lokesh Verma ·2009-02-06 12:32:04

oops yes eureka.. i din look at the full thing.. just saw tension on one and another.. :D

good work..

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karan9989 gupta ·2009-02-06 17:20:33

i got the solution Thanks
But please explain the driving side and the stock side of the belt What does that mean

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62

Lokesh Verma ·2009-02-10 02:14:38

when a belt is rolling, one side is pulling the pulley.. the other is just moving.. the one that is pulling is called the driving side ...

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