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Interesting indeed!
a particle is moving in a circular path of constant tangential acceleration time t after the beginning of motion the direction of net acceleration is at 30° to the radius vector at that instant The angular acceleration of the particle at that time t is
Please give the solution
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2 Answers
33Absurd reply... [3]
velocity of particle after time t (assuming at time t=0 v=0..)
v=at
now tang acc= a
radial acc= v2/R = (at)2/R
tan30°=a/((at)2/R)
1/√3=aR/a2t2=R/at2
a=√3R/t2..
lol.. :D
found anything interseing about it[3]
assumed a= const in begining (also use v=at for that..) and gave final acc as a function of time... :D