130 ) A
10 Answers
1Anirudh can u pls verify my answers for now ???
If it is correct...i'll post the soln.
1the second one is like hcv example problem
just replaced by groove instead of rod
1F X R =12 MR2\alpha
= 12 Ma
F = 12 Ma → a = 2g
v2 - u2=2as
u = 0,
v=\omega R
a=2g
S = length of string.
now substitute , we get S = \omega^{2} R^{2}/4g
1sorry aveek. that was not intentional .
thanks manmay and gr8dreams
30) A
31) A
please solve 31 one
1conserve angular momentum about the centre of rod and it's done.