24Conserving the angular momentum about pivot,
Jx=ml2ω/3
also,vcm=ωl/2
=> mvcm(x-l/2)-ml2ω/12=0
=>x=2l/3
a uniform rod of length L is pivoted at point A . it is struck by a horizontal force which delivers an impulse J at a distance X from point A, impulse deleivered by pivot is zero if X will be .............
(a) L/2 (b) L/3
(c) 2L/3 (d) 3L/4
-
UP 0 DOWN 0 0 5
5 Answers
24
62the answer to this one is the center of gyration.. I am not sure about this one right nwo..
But to solve it from first principle do this:
take the point of the top to give no angular impulse..
Then also J=MωL/2
Then you have to use that J.X=ML2/3ω
3JX/2L=MLω/2
J=3JX/2L
X=2/3L
