rotational mech

none of my answers seem to match with the options given :(

5 Answers

1
Rohan Ghosh ·

Are the answers these ?

1>a
2>a
3-- cannot be seen

here is my process

for the first one

JR=Iw

but w=2Ï€

R=5/2cm=5/2(10-2)m

J=1*sinθ=4/5

replacing the valkues we get the answer

for the second one just complete the prism by turning it into a cuboid

thus now the prism consists of a cuboid and a nagetive mass M

thus

M(32)/12+M(42)/12-I=I

we know the valueof I

thus we get the value of M

33
Abhishek Priyam ·

:)

the main point was to find moi.. :)

1
Philip Calvert ·

[9] maybe he thot it was too mundane to mention

one small thing abhishek......can you help me here

http://targetiit.com/iit_jee_forum/posts/full_test_3_d_3220.html

i know it is some small or silly mistake that i have done

1
Vivek ·

rohan,one doubt,can u explain this
"M(32)/12+M(42)/12-I=I"

1
satan92 ·

I think he means if the moment of inertia of the prism is I and we place two prisms side by side then we get moi = 2I but placing two prisms side by side just makes it a cuboid with moi =

Ml2/12 + Mb2/12

thus

2I=Ml2/12 + Mb2/12

as we know I ,l, b we get M ..

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