1no yaar the question said vertical only.
A uniform bar is pivoted about one end. Initially it is held vertical and allowed to fall. When its angular displacement is 180°, its acceleration is
a) g b) 2g c) 3g d) 4g
sry i can't confirm the answer
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9 Answers
106i am assuming you wanted to ask :
A uniform bar is pivoted about one end. Initially it is held horizontal and allowed to fall. When its angular displacement is 180°, its acceleration is
??
1dunno the answer....method to batao kaise aaya wo....i don't hav the answer..sry about that [2]
1i m not sure, let me think
check with this;;
By cons of energy ω2=6g/L;
dm=(m/L) dx
Centrifugal force=∫dm ω2x (0 to L)
net force downward is mg+centrifugal force= 4 Mg
1You do not have any answer.It means that this problem has been framed by you.
1Two particles of mass m & 2m r fixed to a thin uniform circular loop of mass m & radius(15/11) cm at its diametrically opposite ends.The velocity of centre of the loop is v when it is in pure rolling. find the max. value of v so that the loop does not loose contact with the ground.