s.h.m

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a particle of mass 2 kg undergoes s.h.m according to x = 1.5 sin(Ï€t/4 + Ï€/6 ) wat is the shortest time required for the particle to move from x = 0.5 m to x= -0.75 m

#Physics #Mechanics

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9 Answers

1

big looser ......... ·2009-02-04 10:32:56

koi to reply karo

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33

Abhishek Priyam ·2009-02-04 10:35:51

bahut hi ganda answer..

(sin^-1(1/3)+Ï€/6)*(8/2Ï€)

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1

big looser ......... ·2009-02-04 10:40:09

abhi............... tel me the sol

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chakde ·2009-02-04 10:40:28

SUBSTITUTE X₁ FIND T₁ ;

REPEAT FOR x₂ ; FIND T2

T2-T₁ = t = ans....

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33

Abhishek Priyam ·2009-02-04 10:41:43

answer sahi hai...[7]

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big looser ......... ·2009-02-04 10:48:24

don't know about the right answer but mera answer kuj aur hai

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big looser ......... ·2009-02-04 10:50:33

now i got it............. thanks to both of you

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big looser ......... ·2009-02-04 11:00:52

answer sin k terms mein nai dia. numerical value di hai 0.28 sec

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Abhishek Priyam ·2009-02-04 11:02:25

okie..

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Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

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+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω