1before the wind blows v = ω √(A2-S2)
after the wind it gets an impulse and the new vel v' = ω √(A'2-S2) = 2v
(assuming mean position and time period remaining same)
squaring A'2 = 4A2 - 3S2
or A' = (4A2 - 3S2)1/2
A particle is moving in a straight line with SHM of amplitude A . At a distance S from the centre of motion, the particle receives a blow in direction of the motion which instantaneously doubles the velocity. The new amplitude is?
answer - (4A2 - 3S2)1/2
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4 Answers
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1Hey how can you assume that time period/angular frequency remains same???
1why should angular frequency change??? it is solely an external affair and depends on the source (pity much similar to mechanical waves) :)