21Sorry [2]
its......
PR
PS
Q
match the fol. here.......
EK AUR ........
Displacement - Velocity Equation of a particle :
x = √k - k'V2
k,k' are const.
FIND Time Period T
-
UP 0 DOWN 0 0 11
11 Answers
13x and y ki values dal de its pretty clear
superpose karake dekh
21yeh!! ho gaya..... easy tha re.........
BTW Q2 ka kuch karo naaaaaa
1well, here is my solution... see if it helps...!!!
\frac{\partial x}{\partial t} = \frac{\sqrt{k-x^{2}}}{\sqrt{k'}}
integrating d above equation implies
\sin^{-1}\frac{\sqrt{k}}{x} = \frac{t}{\sqrt{k'}}
x = \sqrt{k}.cosec\frac{t}{\sqrt{k'}}
hence the time period = 2Π√k'...
21YOUr Ans is Perfect but I didnt get ur First step only .... [2]
1just try to isolate 'v' from d given equation... and put v = dx/dt ... and then integrate... it'll b done... [1]