Vectors-Please Help me out

Four forces of magnitude P,2P,3P and 4P act along the four sides of square ABCD in cyclic order.Use the vector method to find the resultant force.

4 Answers

262
Aditya Bhutra ·

P\hat{i} + 2P\hat{j} + 3P(-\hat{i}) + 4P(-\hat{j}) = - (2P\hat{i} + 2P\hat{j})

\left| - (2P\hat{i} + 2P\hat{j})\right| = 2\sqrt{2}P

PS : you cannot find resultant force since the directions are not specified . only magnitude can be found .

71
Vivek @ Born this Way ·

Aditya, By polygon law of vector addition, shouldn't the resultant be zero?

262
Aditya Bhutra ·

the forces have directions as that of the sides of a square,
but since their magnitudes are not same they will not exactly cancel out each other .

158
Anik Chatterjee ·

ya....the correct answr given is 2√2P....and the force is acting at an angle of 225° wen measured from positive x-axis.

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