2 Answers
Ketan Chandak
·2013-03-04 22:13:22
Stopping potential= hxf-(work function)
therefore,2=12475/2500-x
x=3eV.(if 12475/500 is approximated to 5)
Max wavelength is (12475/3)=4159 Angstrom
third part will be ((12475/1000)-2)V=10.475V
- Ketan Chandak sorry 12475/2500Upvote·0· Reply ·2013-03-04 22:13:47
- Akash Anand Good Work
Gaurav Gardi
·2013-03-04 22:31:14
(i)3eV(approx)
(ii)4158.33 or(4158 approx).
(iii)10.475V
- Akash Anand Good Work