?????????

JEE Mains Forum › Optics questions › ?????????

a short linear object of length b lies along axis of a concave mirror of focal length f at a distance u from the pole of mirror.The size of image is aprox. equal to???

#Physics #Optics

UP 0 DOWN 0 0 8
Post on FacebookPost anonymously?

8 Answers

1

Pavithra Ramamoorthy ·2009-03-31 19:50:27

fb/u ???????

UP 0 DOWN 0
Post on FacebookPost anonymously?

24

eureka123 ·2009-03-31 19:56:20

no

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

ankit mahapatra ·2009-03-31 20:01:43

book main hai solution bataun ya hint dun

UP 0 DOWN 0
Post on FacebookPost anonymously?

24

eureka123 ·2009-03-31 20:05:08

agar tu previous year vale soln ki baat kar raha hai to sirf samjha de.......

agar kuch aur to pura soln post kar de...

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

ankit mahapatra ·2009-03-31 20:11:53

first take mirror forumula and differentiate it with respect to x.
you get

|dv|=|v²/u²| *|du|

|dv|=size of the image
|du|=b

another form of mirror formula:

(v²/u²)=(f/u-f)²

now substitue the values

UP 0 DOWN 0
Post on FacebookPost anonymously?

24

eureka123 ·2009-03-31 20:18:57

ya explain that...........how mod (dv) is size of image???????

UP 0 DOWN 0
Post on FacebookPost anonymously?

1

ankit mahapatra ·2009-03-31 20:58:29

|dv| is taken because it is a short linear object.

UP 0 DOWN 0
Post on FacebookPost anonymously?

24

eureka123 ·2009-03-31 21:46:54

ok....i got that now.........thanx

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω