1/v - 1/(-45)=1/30
therefore v will be 90.....
now this will act as an object for the second lens
1/v - 1/15=1/(-30)
u will get v as 30
therefore the image will be formed at (90+30)=120.....
(i think this is the answer)
A thin convex lens whose focal length in air is known to be 30cm is cut into two parts by a transverse plane parallel to principal axis and 0.5cm above the principal axis. They are placed on the x-axis a shown in the figure.A point object is placed on the origin of the coordinate system.Find the co-ordinates of the final image formed due to the rays which get refracted by both the parts of the lens (assuming paraxial ray approximations to be valid)
Oh yeah, i made big mistakes :P
Akshay, which part of the lens is placed where....Is it given ?
1/v - 1/(-45)=1/30
therefore v will be 90.....
now this will act as an object for the second lens
1/v - 1/15=1/(-30)
u will get v as 30
therefore the image will be formed at (90+30)=120.....
(i think this is the answer)
nopes !!
i hav mentioned all the data above which is given in the question .
nothing else is given... bro.
I was going in the same way as urs ......
but buddy answer given is that final image is formed at (120cm, -1cm)
The -1 can be calculated by finding out the magnifications on consecutive refractions-0.5-0.5